-55x^2+45x-40=-60x^2-5x

Solution for -55x^2+45x-40=-60x^2-5x equation:

-55x^2+45x-40=-60x^2-5x

We move all terms to the left:

-55x^2+45x-40-(-60x^2-5x)=0

We get rid of parentheses

-55x^2+60x^2+5x+45x-40=0

We add all the numbers together, and all the variables

5x^2+50x-40=0

a = 5; b = 50; c = -40;
Δ = b2-4ac
Δ = 502-4·5·(-40)
Δ = 3300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3300}=\sqrt{100*33}=\sqrt{100}*\sqrt{33}=10\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-10\sqrt{33}}{2*5}=\frac{-50-10\sqrt{33}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+10\sqrt{33}}{2*5}=\frac{-50+10\sqrt{33}}{10}
$